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Jul 13, 2018 at 17:52 answer added AYO timeline score: 1
Feb 7, 2013 at 9:08 vote accept Andrew
Feb 5, 2013 at 23:31 answer added Samuel Vidal timeline score: 1
Feb 4, 2013 at 3:40 answer added Ira Gessel timeline score: 3
Feb 4, 2013 at 2:55 comment added Max Alekseyev It look to me that the given counting for labeled bipartite graphs is incorrect. Labeling of vertices does not imply particular partition of the vertices into V_1 and V_2. E.g., an isolated vertex may be viewed as belonging to V_1 or V_2 but that does not change the graph.
Feb 3, 2013 at 17:39 comment added Carl Feynman In the limit for large $n$, the average graph has no automorphisms, so the number of unlabeled graphs is simply the number of labeled graphs divided by the number of possible labelings, i.e. $n!$.
Feb 3, 2013 at 17:06 answer added Samuel Vidal timeline score: 0
Feb 3, 2013 at 15:47 comment added Steve Huntsman oeis.org/A005142
Feb 3, 2013 at 15:46 comment added Steve Huntsman oeis.org/A033995
Feb 3, 2013 at 15:20 history asked Andrew CC BY-SA 3.0