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Feb 5, 2013 at 3:40 vote accept anonymous
Feb 4, 2013 at 7:20 comment added IMeasy By def, $E$ is lin. eq. to the pull-back of the intersection of an hyperplane with the image of $X$. This is what is - with a little abuse of terminology - known as hyperplane divisor.
Feb 3, 2013 at 19:12 comment added anonymous I am sorry if this is pedantic, but I do not see why the definition of $\phi$ makes $E$ the pull-back of a hyperplane in $\mathbb{P}^N$.
Feb 3, 2013 at 9:16 history answered IMeasy CC BY-SA 3.0