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Oct 17, 2021 at 23:09 comment added Roxana Dear @DustinCartwright can you suggest me a reference where to read in a detailed way about you said?
S Jan 12, 2014 at 20:47 history suggested Jeroen Zuiddam CC BY-SA 3.0
Added missing index i and improved formatting of Spec
Jan 12, 2014 at 20:47 review Suggested edits
S Jan 12, 2014 at 20:47
Feb 5, 2013 at 3:40 vote accept anonymous
Feb 3, 2013 at 19:17 comment added anonymous Why is the dual space more appropriate?
Feb 3, 2013 at 15:30 comment added Dustin Cartwright A minor correction regarding your last comment: the $\mathbb P^N$ which is the image of $\phi$ should be identified with the dual of $\lvert D_0\rvert$. Of course, these are both projective spaces of the same dimension, but they are not canonically isomorphic.
Feb 3, 2013 at 9:16 answer added IMeasy timeline score: 2
Feb 3, 2013 at 0:24 comment added Vesselin Dimitrov I mean, $E = \phi^* H$.
Feb 3, 2013 at 0:22 comment added Vesselin Dimitrov Saying that $E$ is linearly equivalent to $D$ means that you can find a hyperplane $H$ in $\mathbb{P}^N$ such that $E = f^*H$. Now, either $H$ contains the point $\phi(C)$, or it doesn't.
Feb 3, 2013 at 0:14 history asked anonymous CC BY-SA 3.0