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Feb 1, 2013 at 8:46 vote accept Werner Thumann
Feb 1, 2013 at 8:45 comment added Werner Thumann Fernando, thank you for your help, I will think over all this.
Feb 1, 2013 at 8:08 comment added Fernando Muro @Werner, free crossed modules are a special case of what you propose, hence the computation above works as a counterexample too. BTW, I think that, in general, free objects are not better behaved for this king of question, because they are universal examples, hence anything that fails in general fails also for free ones.
Jan 31, 2013 at 22:55 comment added Werner Thumann @ Fernando, Chris, Evan: Thank you for your answers. Oh yes, this question is ill-posed. Consider e.g. the free 2-group generated by an object A and an iso from I to A. Then pi_1 is trivial and pi_2 also, so it is 2-equivalent to the trivial 2-group. But in the first case, the group I defined is ZxZ and in the second case trivial. Can someone confirm this. But maybe I can rescue a bit of the question by restricting to 2-groups freely gen. by some objects and some isos between tensor expressions of these objects. Can something be said in this case?
Jan 31, 2013 at 21:03 history answered Fernando Muro CC BY-SA 3.0