Timeline for On Weil's characters of type (A)
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
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Feb 15, 2014 at 18:18 | history | edited | Keerthi Madapusi | CC BY-SA 3.0 |
improved formatting
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Jan 31, 2013 at 23:05 | vote | accept | Hugo Chapdelaine | ||
Jan 31, 2013 at 21:23 | comment | added | Keerthi Madapusi | Also, as Florian points out in the comments above, pretty much the same proof appears in Patrikis's thesis. | |
Jan 31, 2013 at 21:13 | comment | added | Keerthi Madapusi | Edits made. I think the proof is now correct. | |
Jan 31, 2013 at 21:12 | history | edited | Keerthi Madapusi | CC BY-SA 3.0 |
added 1498 characters in body; deleted 221 characters in body
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Jan 31, 2013 at 20:25 | comment | added | Keerthi Madapusi | Hi Hugo, you're right! I was confused about why I seemed to be getting post facto that $f_{\sigma\iota}+f_{\bar{\sigma}\iota}$ was independent also of $\sigma$. But of course I need to show this a priori! I'll see if I can fix the argument. | |
Jan 31, 2013 at 17:10 | comment | added | Hugo Chapdelaine | Hi Keerthi, I'm confused about one point. If $Stab(f)=H\leq G_{\mathbf{Q}}$, then you are showing that for all complex conjugation $c\in G_{\mathbf{Q}}$, $cHc^{-1}=H$. But this does not seem to imply that $L:=\bar{\mathbf{Q}}^{H}$ is a CM field. For example, if $L$ is Galois over $\mathbf{Q}$ and not CM, then the condition $cHc^{-1}=H$ is trivially satisfied since $H$ is normal in $G_{\mathbf{Q}}$. Am I right? | |
Jan 31, 2013 at 1:38 | history | answered | Keerthi Madapusi | CC BY-SA 3.0 |