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José Hdz. Stgo.
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I think the best example of this will be the fundamental theorem of aithmeticarithmetic: the assertion that every natural number greater than 1 is either prime or the product of primes (and uniquely so).

Proof of existence is by strong induction. Assume true below n. If n is prime, we're done. Otherwise, n = ab for some a,b < n, and by induction these are products of primes, so n is also. QED (and no need for special anchor case).

Proof of uniqueness does not use induction.

I think the best example of this will be the fundamental theorem of aithmetic: the assertion that every natural number greater than 1 is either prime or the product of primes (and uniquely so).

Proof of existence is by strong induction. Assume true below n. If n is prime, we're done. Otherwise, n = ab for some a,b < n, and by induction these are products of primes, so n is also. QED (and no need for special anchor case).

Proof of uniqueness does not use induction.

I think the best example of this will be the fundamental theorem of arithmetic: the assertion that every natural number greater than 1 is either prime or the product of primes (and uniquely so).

Proof of existence is by strong induction. Assume true below n. If n is prime, we're done. Otherwise, n = ab for some a,b < n, and by induction these are products of primes, so n is also. QED (and no need for special anchor case).

Proof of uniqueness does not use induction.

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Joel David Hamkins
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I think the best example of this will be the fundamental theorem of aithmetic: the assertion that every positive natural number greater than 1 is either prime or the product of primes (and uniquely so).

Proof of existence is by strong induction. Assume true below n. If n is prime, we're done. Otherwise, n = ab for some a,b < n, and by induction these are products of primes, so n is also. QED (and no need for special anchor case).

Proof of uniqueness does not use induction.

I think the best example of this will be the fundamental theorem of aithmetic: the assertion that every positive natural number is either prime or the product of primes (and uniquely so).

Proof of existence is by strong induction. Assume true below n. If n is prime, we're done. Otherwise, n = ab for some a,b < n, and by induction these are products of primes, so n is also. QED (and no need for special anchor case).

Proof of uniqueness does not use induction.

I think the best example of this will be the fundamental theorem of aithmetic: the assertion that every natural number greater than 1 is either prime or the product of primes (and uniquely so).

Proof of existence is by strong induction. Assume true below n. If n is prime, we're done. Otherwise, n = ab for some a,b < n, and by induction these are products of primes, so n is also. QED (and no need for special anchor case).

Proof of uniqueness does not use induction.

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Joel David Hamkins
  • 236.2k
  • 44
  • 777
  • 1.4k

I think the best example of this will be the fundamental theorem of aithmetic: the assertion that every positive natural number is either prime or the product of primes (and uniquely so).

Proof of existence is by strong induction. Assume true below n. If n is prime, we're done. Otherwise, n = ab for some a,b < n, and by induction these are products of primes, so n is also. QED (and no need for special anchor case).

Proof of uniqueness does not use induction.