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Feb 1, 2013 at 0:31 comment added Matt Jacobs Thank you for the great diagram and explanation. Is there a reason that this problem becomes easy again for $C^{\infty}$ functions?
Feb 1, 2013 at 0:30 vote accept Matt Jacobs
Jan 31, 2013 at 17:36 comment added Terry Tao ... and so one cannot hope for really sharp criteria based only on the magnitude of individual Fourier coefficients. (However, thanks to Littlewood-Paley theory, which has much better L^p stability properties than the Fourier transform, one can get good control in terms of Littlewood-Paley components of the function, as Bazin points out below. )
Jan 31, 2013 at 17:34 comment added Terry Tao As a general rule, the further away the integrability exponent $p$ of a physical space-based function space is from the Hilbert exponent $2$, the harder it is to control the norm via the magnitude of the Fourier coefficients (basically because analogues of the Plancherel identity, such as the Hanner inequalities or the Hausdorff-Young inequalities, become less and less efficient as one moves further away from 2). The Holder classes have exponent $\infty$ (as depicted for instance in this diagram of mine: terrytao.wordpress.com/2010/03/11/… ) ...
Jan 30, 2013 at 21:10 history edited Pietro Majer CC BY-SA 3.0
edited body; edited title
Jan 30, 2013 at 20:29 answer added Bazin timeline score: 11
Jan 30, 2013 at 19:44 answer added Gian Maria Dall'Ara timeline score: 5
Jan 30, 2013 at 17:37 answer added Daniel Spector timeline score: 5
Jan 30, 2013 at 16:28 history asked Matt Jacobs CC BY-SA 3.0