Skip to main content
11 events
when toggle format what by license comment
S Jan 15, 2018 at 9:18 history suggested Ali Taghavi
I add a tag
Jan 15, 2018 at 7:39 review Suggested edits
S Jan 15, 2018 at 9:18
Jan 28, 2013 at 17:24 comment added Asghar Ghorbanpour Thanks for the useful references. However, I still wondering if there is a bound like $l$ such that pseudo differential operator of the order $d$ is in the Dixmier ideal (not necessary measurable) when $d<l$. of course $l$ should be in $[-k,0)$ where $k=dim M$.
Jan 28, 2013 at 10:30 comment added Branimir Ćaćić Moreover, by the Connes trace formula (alainconnes.org/docs/action88.pdf), if your operator is of order $-k$ for $k = \dim M$, then it is in the Dixmier ideal; indeed, it is measurable (in the sense of the theory of Dixmier traces), and the (unique value of the) Dixmier trace is given by the Wodzicki residue of your operator.
Jan 28, 2013 at 5:09 history edited Otis Chodosh
edited tags
Jan 28, 2013 at 5:06 answer added Rafe Mazzeo timeline score: 6
Jan 28, 2013 at 4:22 history edited Asghar Ghorbanpour CC BY-SA 3.0
edited title
Jan 27, 2013 at 11:33 answer added Bazin timeline score: 5
Jan 26, 2013 at 21:53 history edited Asghar Ghorbanpour CC BY-SA 3.0
edited title
Jan 26, 2013 at 14:43 comment added Liviu Nicolaescu It is trace class when it is an operator of order $-k$, $k>\dim M$. For a proof see Section 4.3 of these notes www3.nd.edu/~lnicolae/Pseudo.pdf
Jan 25, 2013 at 23:46 history asked Asghar Ghorbanpour CC BY-SA 3.0