Timeline for When is a Pseudo-differential operator trace class or in Dixmier ideal?
Current License: CC BY-SA 3.0
11 events
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S Jan 15, 2018 at 9:18 | history | suggested | Ali Taghavi |
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Jan 15, 2018 at 7:39 | review | Suggested edits | |||
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Jan 28, 2013 at 17:24 | comment | added | Asghar Ghorbanpour | Thanks for the useful references. However, I still wondering if there is a bound like $l$ such that pseudo differential operator of the order $d$ is in the Dixmier ideal (not necessary measurable) when $d<l$. of course $l$ should be in $[-k,0)$ where $k=dim M$. | |
Jan 28, 2013 at 10:30 | comment | added | Branimir Ćaćić | Moreover, by the Connes trace formula (alainconnes.org/docs/action88.pdf), if your operator is of order $-k$ for $k = \dim M$, then it is in the Dixmier ideal; indeed, it is measurable (in the sense of the theory of Dixmier traces), and the (unique value of the) Dixmier trace is given by the Wodzicki residue of your operator. | |
Jan 28, 2013 at 5:09 | history | edited | Otis Chodosh |
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Jan 28, 2013 at 5:06 | answer | added | Rafe Mazzeo | timeline score: 6 | |
Jan 28, 2013 at 4:22 | history | edited | Asghar Ghorbanpour | CC BY-SA 3.0 |
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Jan 27, 2013 at 11:33 | answer | added | Bazin | timeline score: 5 | |
Jan 26, 2013 at 21:53 | history | edited | Asghar Ghorbanpour | CC BY-SA 3.0 |
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Jan 26, 2013 at 14:43 | comment | added | Liviu Nicolaescu | It is trace class when it is an operator of order $-k$, $k>\dim M$. For a proof see Section 4.3 of these notes www3.nd.edu/~lnicolae/Pseudo.pdf | |
Jan 25, 2013 at 23:46 | history | asked | Asghar Ghorbanpour | CC BY-SA 3.0 |