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S Dec 1, 2023 at 14:27 history suggested The Amplitwist CC BY-SA 4.0
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S Dec 1, 2023 at 14:27
Jan 26, 2013 at 6:04 comment added Aaron Meyerowitz Obviously more difficult than I thought also.
Jan 25, 2013 at 22:23 comment added Sam Hopkins @AaronMeyerowitz: I now see why this question is more difficult than I thought at first. Thanks.
Jan 25, 2013 at 20:58 comment added Aaron Meyerowitz @SamHopkins. There are $38$ connected subgraphs of $K_4$. If I pick, choosing uniformly among them, and then pick uniformly among the spanning trees of that subgraph , then the probability of getting a star is 41/152. If I pick a spanning tree by randomly weighting the edges and then taking the minimal cost spanning tree then the probabilities are something else but almost surely not uniform.
Jan 25, 2013 at 2:18 vote accept Felix Goldberg
Jan 25, 2013 at 2:16 answer added Aaron Meyerowitz timeline score: 5
Jan 25, 2013 at 0:30 comment added Felix Goldberg @SamHopkins: Actually, I was thinking about unlabelled...
Jan 25, 2013 at 0:03 comment added Sam Hopkins I assume you're considering labeled trees/graphs. Here's an answer for an easier version of the question, which maybe you have already considered: suppose you choose each connected graph on n vertices with equal probability, and suppose you choose from it a random spanning tree. Then it seems clear to me that all trees are equally likely.
Jan 24, 2013 at 23:54 history asked Felix Goldberg CC BY-SA 3.0