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Jan 23, 2013 at 18:31 vote accept Sayan
Jan 23, 2013 at 18:31 vote accept Sayan
Jan 23, 2013 at 18:31
Jan 23, 2013 at 18:10 answer added Ollie timeline score: 4
Jan 23, 2013 at 17:14 comment added Alain Valette If $U$ is your partial isometry on $H$, I don't see what prevents you from defining a partial isometry $S(U)$ on $e^H$ by $S(U)(\oplus_{n=0}^\infty(\xi_1\otimes...\otimes\xi_n)=\oplus_{n=0}^\infty(U\xi_1\otimes...\otimes U\xi_n)$.
Jan 23, 2013 at 16:39 history asked Sayan CC BY-SA 3.0