Timeline for Visualizing polyhedra from their 1-skeletons
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 28, 2017 at 15:29 | answer | added | Joseph Malkevitch | timeline score: 2 | |
| Mar 27, 2017 at 14:52 | answer | added | Ian Agol | timeline score: 8 | |
| Sep 10, 2015 at 12:08 | answer | added | Igor Rivin | timeline score: 3 | |
| Sep 10, 2015 at 10:40 | answer | added | Sergey P. Shary | timeline score: 4 | |
| Mar 28, 2013 at 10:11 | answer | added | Zsbán Ambrus | timeline score: 4 | |
| Mar 26, 2013 at 18:31 | answer | added | Vince Matsko | timeline score: 8 | |
| Jan 21, 2013 at 14:11 | comment | added | Joseph O'Rourke | @Hans: Yes, they are all "the same" in the sense of being combinatorially equivalent. But their visual representations can differ drastically. | |
| Jan 21, 2013 at 13:35 | comment | added | Hans-Peter Stricker | @Joseph: I was thinking of something like a "prototype". (Of course one can distort a given polyhedron, but basically they are all the same, aren't they?) | |
| Jan 21, 2013 at 13:18 | comment | added | Joseph O'Rourke | @Hans: The way you write "the polyhedron" suggests you might be forgetting that these graphs are realized by an infinite variety of combinatorially equivalent polyhedra. | |
| Jan 21, 2013 at 13:16 | answer | added | Joseph O'Rourke | timeline score: 9 | |
| Jan 21, 2013 at 12:52 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
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| Jan 21, 2013 at 11:44 | comment | added | user22882 | Hexahedral graph 5: Take a tetrahedron, glue on one of its faces another tetrahedron and on that one a third tetrahedron, such that the three tetrahedra have one edge in common. Visualisation worked for me because I recognised the graph of the tetrahedron in the heahedral graph. This may be part of a technique. | |
| Jan 21, 2013 at 11:20 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
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| Jan 21, 2013 at 10:58 | history | asked | Hans-Peter Stricker | CC BY-SA 3.0 |