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Apr 13, 2017 at 12:58 history edited CommunityBot
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Aug 11, 2014 at 21:56 comment added Ilias A. Here is an "easy" argument in the case of topological space (that you can perform in the stable motivic category). Suppose that $R$ is an $E_{\infty}$ ring spectrum and $X$ is a space, use the internal Hom $F(-.-)$ in the category of spectra, then $F(\Sigma^{\infty} X_{+}, R)$ is an $E_{\infty}$ ring spectrum, since $\Sigma^{\infty} X_{+}$ is an $E_{\infty}$ coalgebra.
Aug 11, 2014 at 21:36 comment added Ilias A. You should take a look to this article by Joshua Roy (Theorem 1.1) The Rational and Integral motivic complex. In the rational case it is represented by commutative DGA over Q (since zoo can always strictify over rationals) and the second is represented by $E_{\infty}$-differential graded $\mathbf{Z}$-algebra. $people.math.osu.edu/joshua.1/mdga_short.pdf
Jan 21, 2013 at 4:58 vote accept Mikhail Bondarko
Jan 20, 2013 at 23:38 answer added Marc Hoyois timeline score: 8
Jan 20, 2013 at 21:24 history asked Mikhail Bondarko CC BY-SA 3.0