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Jan 25, 2013 at 1:19 comment added Greg Martin Indeed, Toth seems to have proved this statement (about $n$ randomly chosen integers being pairwise coprime) in a 2002 Fibonacci Quarterly paper. ams.org/mathscinet-getitem?mr=1885265
Jan 22, 2013 at 1:28 comment added Greg Martin The formula in the answer certainly reduces, when $k=2$ (pairwise coprime), to $\prod_q (1-q^{-1})^{n-1}(1+(n-1)q^{-1})$, validating Finch's statement.
Jan 21, 2013 at 2:11 comment added Alex G Nice. Even though as you might have guessed, I was hoping for an answer involving the zeta function.
Jan 21, 2013 at 2:09 vote accept Alex G
Jan 20, 2013 at 22:13 comment added Gerry Myerson This .286747... is also the probability that two positive integers are "strongly carefree," that is, coprime and both squarefree, see Finch, Mathematical Constants, p. 110. Next page, Finch notes the probability $k$ integers are pairwise coprime is $\prod(1-p^{-1})^{k-1}(1+(k-1)p^{-1})$ for $k=2,3$, unproved for $k\gt3$. Some of Finch's references are to unpublished work of Moree. A published reference is Schroeder's book, Number Theory in Science and Communication, pp 25, 48-51, and 54.
Jan 20, 2013 at 20:13 history answered Greg Martin CC BY-SA 3.0