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May 19, 2020 at 16:34 comment added Taras Banakh On the other hand, for any ordinal $\alpha$ the compactness of the Tychonoff cube $[0,1]^\alpha$ can be proved without AC or BPIT, usinng the completeness of the lexicographic order on $[0,1]^\alpha$ (or even on $\{0,1\}^\alpha$).
Jan 20, 2013 at 2:09 vote accept Alexey Muranov
Dec 13, 2014 at 15:01
Jan 19, 2013 at 21:54 history answered Asaf Karagila CC BY-SA 3.0