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Mar 9, 2014 at 15:11 review Close votes
Mar 9, 2014 at 20:34
Mar 9, 2014 at 14:54 comment added Douglas Zare $c(m) N^m$ obviously can't be a lower bound, since $N^m/N$ is an upper bound. You can also rule out $c(N) N^m.$ The CLT tells you what to expect.
Mar 8, 2014 at 21:57 answer added mathse timeline score: 1
Jan 19, 2013 at 7:20 answer added matthias beck timeline score: 2
Jan 17, 2013 at 0:56 history asked user30706 CC BY-SA 3.0