Timeline for Can a zerodivisor reduce both the depth and the dimension?
Current License: CC BY-SA 3.0
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| Jan 17, 2013 at 2:06 | history | edited | Allen Knutson | CC BY-SA 3.0 |
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| Jan 17, 2013 at 1:54 | history | edited | Allen Knutson | CC BY-SA 3.0 |
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| Jan 17, 2013 at 1:46 | history | edited | Allen Knutson | CC BY-SA 3.0 |
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| Jan 17, 2013 at 1:28 | comment | added | Sándor Kovács | @Allen: $\mathrm{depth}$ is usually considered over a local ring and in fact, the question includes that assumption. The $x$ in your example seems like a red herring. It's only a zero-divisor away from where the interesting thing is happening. In particular, I don't see why it would be a zero-divisor after localizing at the point where you are reducing the depth. | |
| Jan 16, 2013 at 23:59 | history | answered | Allen Knutson | CC BY-SA 3.0 |