Timeline for The set of orders of elements in a group
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 16, 2013 at 20:31 | comment | added | Todd Trimble | @shatich: it does affect the problem a little, in that the left side of your equation does not read {O($x$): $x \in G$ and $x$ is of finite order}. | |
| Jan 16, 2013 at 18:37 | answer | added | José Hdz. Stgo. | timeline score: 16 | |
| Jan 16, 2013 at 18:32 | vote | accept | CommunityBot | ||
| Jan 16, 2013 at 18:27 | answer | added | Stefan Kohl♦ | timeline score: 13 | |
| Jan 16, 2013 at 18:22 | comment | added | Ramiro de la Vega | For one thing, if $m | n$ and $n \in A$ then $m \in A$. Now you can drop the singleton. | |
| Jan 16, 2013 at 18:19 | comment | added | user30230 | @Todd: Yes. Note that this does not affect the generality of the problem. since if $B = A\cup\lbrace\infty\rbrace$ then $G\oplus\mathbb{Z}$ whould be the answer. | |
| Jan 16, 2013 at 18:07 | comment | added | Todd Trimble | Just checking: you're requiring every element $x$ in $G$ to be of finite order? | |
| Jan 16, 2013 at 17:55 | history | asked | user30230 | CC BY-SA 3.0 |