Timeline for Can the finiteness of a Burnside group with two generators be checked algorithmically by using Fuchsian von Dyck groups?
Current License: CC BY-SA 3.0
7 events
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Sep 9, 2014 at 4:10 | vote | accept | Giovanni Moreno | ||
| Sep 7, 2014 at 8:49 | answer | added | HJRW | timeline score: 1 | |
| Sep 5, 2014 at 7:35 | history | edited | Giovanni Moreno | CC BY-SA 3.0 |
Previous question, titled "Coverings of the free Burnside groups", was never answered. So, I reformulate it adding new details I discovered meanwhile.
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| Jan 17, 2013 at 17:33 | comment | added | Giovanni Moreno | Misha, thanks for the information: does the group you've mentioned have a name? And yet Question 1 is still unanswered... Since von Dyck groups can be seen as groups of isometries of constant-curvature surfaces, the epimorphism I'm interested in allows to regard free Burnside groups as groups of transformations of suitable orbifolds: in this perspective, the generalization of the von Dyck group I'm looking for should give a group of isometries of some geometrical object. Does this graph-construction of your admit such an interpretation? | |
| Jan 17, 2013 at 6:38 | comment | added | Misha | The most natural generalization is: Take a finite graph on $m$ vertices; declare each vertex $v$ to be a generator; take relators $v^n=1$ for every vertex and $(vw)^n=1$ for every pair of vertices corresponding to an edge. Then von Dyck groups $D(n,n,n)$ correspond to the case of a graph consisting of a single edge. All this is quite trivial, the question is what are you going to do with such groups. | |
| Jan 16, 2013 at 16:32 | history | asked | Giovanni Moreno | CC BY-SA 3.0 |