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Jan 16, 2013 at 9:05 vote accept TOM
Jan 15, 2013 at 17:20 comment added David Loeffler @pranavk: Sorry, didn't see your comment -- you said considerably more than I did in less space!
Jan 15, 2013 at 17:18 answer added David Loeffler timeline score: 10
Jan 15, 2013 at 17:16 comment added user30379 Addendum to previous comment: one can make a variant in the good ordinary reduction case, except that the case of decomposable $V_p(E)$ (i.e., Serre-Tate canonical lifts) needs to be excluded. In the multiplicative reduction case there is an affirmative result near the end of Serre's book "Abelian $\ell$-adic representations" (using calculations with Tate curves). The omitted details in my comments are good exercises, so I'll leave it at that.
Jan 15, 2013 at 17:05 comment added user30379 Yes. Consider elliptic curves $E$ over $K=\mathbf{Q}_p$ with good ss reduction, so $V_p(E)$ is irreducible and crystalline with Hodge-Tate weights $0$ and $1$. By a calculation in $p$-adic Hodge theory (for 2-dimensional representations and distinct Hodge-Tate weights), $V_p(E)$ is determined up to abstract isomorphism by the char. polynomial of the linear (!) Frobenius on the Dieudonn\'e module of the reduction $E_0$. But geometric isogeny classes mod isom. are countable and the deformation ring of $E_0$ has uncountably many $\mathbf{Q}_p$-points, so lots aren't $\overline{K}$-isogenous.
Jan 15, 2013 at 17:00 comment added Damian Rössler See mathoverflow.net/questions/53014/…
Jan 15, 2013 at 16:01 history edited Leo Alonso
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Jan 15, 2013 at 16:01 history edited Leo Alonso
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Jan 15, 2013 at 16:00 history edited Leo Alonso
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Jan 15, 2013 at 15:31 history asked TOM CC BY-SA 3.0