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Timeline for Jordan-like cycles in graphs

Current License: CC BY-SA 3.0

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Jan 21, 2013 at 18:17 comment added Will Sawin No. Indeed, it's clear that, for polyhedral graphs, every cycle is either a Jordan curve in each embedding or a curve whose complement has one component, depending on whether it bounds a single face or not.
Jan 21, 2013 at 18:03 comment added Hans-Peter Stricker @Will: Things might look different, if we allow one of the two components to be empty. Does it still hold then, that every planar graphs contains a cycle which does not separate the graph into two components?
Jan 21, 2013 at 17:02 comment added Will Sawin One might also ask if every graph such that each Jordan curve in one planar embedding is a Jordan curve in another planar embedding has this property.
Jan 21, 2013 at 16:35 comment added Will Sawin No such graphs exist, because every planar graph contains a cycle which does not separate the graph into two components, let alone do so in every embedding. I think the right thing to consider is graphs tha thave only one embedding inthe sphere, up to orientation-preserving homotopy. I think it's clear that these are polyhedral graphs, with the edges subdivided, or otherwise something really trivial like a path.
Jan 21, 2013 at 8:59 comment added Hans-Peter Stricker @Will: I'd like to understand better the connection between 3-connected planar graphs and planar graphs in which every cycle is a Jordan cycle. Does it hold - eventually - that in a 3-connected planar graph every cycle is a Jordan cycle? Or can you give a counter-example?
Jan 14, 2013 at 19:16 comment added Ben Barber "Falling prey to unchecked details may be regarded as a misfortune; contradicting the given example looks like carelessness."
Jan 14, 2013 at 19:05 history edited Will Sawin CC BY-SA 3.0
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Jan 14, 2013 at 18:46 history answered Will Sawin CC BY-SA 3.0