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Jan 17, 2013 at 15:53 comment added Lior Bary-Soroker @Berlusconi see the beginning of the answer. @Martin, I agree to what you write, but the vector space approach is as simple.
Jan 15, 2013 at 1:14 comment added Martin Brandenburg Yes every dihedral group is generated by two elements of order 2, so we need to use that the group is abelian. If an abelian group is generated by $m$ elements and all of them have order $2$, then we get an epimorphism from $\mathbb{Z}/2 \oplus \dotsc \oplus \mathbb{Z}/2$, thus the group has $\leq 2^m$ elements.
Jan 14, 2013 at 18:36 history answered Lior Bary-Soroker CC BY-SA 3.0