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Mar 12, 2021 at 23:35 vote accept Peter Scholze
Jan 22, 2013 at 11:04 answer added Peter Scholze timeline score: 13
Jan 14, 2013 at 20:59 comment added Peter Scholze @Angelo: Thanks for answering the second question, anyway!
Jan 14, 2013 at 20:51 comment added Angelo To Jason: I am never 100% sure I am correct, because I have a tendency to overlook key points; so, the question was not completely rhetorical. To Peter: no reason to be sorry.
Jan 14, 2013 at 20:34 history edited Peter Scholze CC BY-SA 3.0
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Jan 14, 2013 at 20:33 comment added Peter Scholze Whoops. Sorry :-).
Jan 14, 2013 at 20:22 comment added Jason Starr @Angelo: I realize that your question is rhetorical. Perhaps not everybody realizes this. Of course you are correct (as surely you already know). One relevant reference is Proposition 5.10.14, p. 119 of EGA IV_2 (presumably also "Local cohomology", Grothendieck-Hartshorne, etc.).
Jan 14, 2013 at 20:15 comment added Angelo If $R$ is a complete intersection it is Cohen-Macaulay; it follows that $R$ is the set of sections of the structure sheaf of $\mathop{\rm Spec}R \smallsetminus \{x\}$, since $\{x\}$ has codimension 2. Am I missing something?
Jan 14, 2013 at 20:03 comment added Peter Scholze No -- it is not true in general that $R$ is the set of global sections of $\mathrm{Spec} R$ - $x$. One example (which is of course not a complete intersection) is $R=k[X^2,X^3,XY,Y^2,Y^3]\subset k[X,Y]$. You might also have nilpotents at $x$.
Jan 14, 2013 at 17:37 comment added Angelo About question 2, doesn't it follow by taking global sections of the structure sheaf that $R = k[x,y]$?
Jan 14, 2013 at 16:35 history asked Peter Scholze CC BY-SA 3.0