Timeline for Distributive sublattices of atomistic ortholattices
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 15, 2013 at 15:16 | vote | accept | Carmen | ||
| Jan 14, 2013 at 16:27 | comment | added | Emil Jeřábek | As for edit summaries, they are shown in the revision history of the post, which you can retrieve by clicking on the “edited XXXX ago” link below the post. (The link is not shown if there is only the initial revision; in that case you can type the URL manually, it has the form mathoverflow.net/revisions/XXXX/list where XXXX is the numerical id of the post.) | |
| Jan 14, 2013 at 16:20 | comment | added | Emil Jeřábek | Having one atom is not going to help you, you can modify the example to take all subsets of $\mathbb N$ whose characteristic function is periodic on $\mathbb N-\{0\}$. This algebra has an atom, namely $\{0\}$, but only two of its elements are joins of atoms. (The general form of Nik’s answer is that every Boolean algebra is a subalgebra of a powerset algebra, by the way.) | |
| Jan 14, 2013 at 13:56 | comment | added | Carmen | Yes, good idea about the comment. I understand atomic to mean that $M$ has atoms, while atomistic means that every element is a join of atoms. | |
| Jan 14, 2013 at 13:22 | comment | added | Nik Weaver | Also, when you edit a question to add conditions you should include a comment that you've done so. | |
| Jan 14, 2013 at 13:19 | comment | added | Nik Weaver | Not sure what you mean ... to me, "atomic" means that every element is a join of atoms. | |
| Jan 14, 2013 at 13:07 | comment | added | Carmen | what if I impose the additional condition that $M$ is atomic? | |
| Jan 14, 2013 at 11:30 | history | answered | Nik Weaver | CC BY-SA 3.0 |