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Timeline for Making CW-complexes metrizable

Current License: CC BY-SA 4.0

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Dec 14, 2022 at 15:22 vote accept Jeremy Brazas
Dec 14, 2022 at 13:40 answer added Tyrone timeline score: 5
Dec 13, 2022 at 18:19 comment added Jeremy Brazas @Tyrone Thanks! Please submit this as an answer. I'd like to accept it.
Dec 13, 2022 at 13:39 comment added Tyrone Sure. It's Theorem 2.1 in R. Cauty's Rétractions dans les espaces stratifiables.
Dec 13, 2022 at 13:03 comment added Jeremy Brazas @Tyrone Do you know of a reference? I'm a little skeptical of the final claim if $K$ is say a Sierpinski carpet that fills up a 2-cell.
Dec 13, 2022 at 11:31 comment added Tyrone This is tue. In fact, $X$ (no restriction on its number of cells) admits a continuous metric $d$ so that 1. $X_{Met}=(X,d)$ is an ANR 2. $X\rightarrow X_{Met}$ is a homotopy equivalence 3. $d$ the homotopies witnessing the previous equivalence can be chosen to fix pointwise any given compact subset $K\subseteq X$.
Sep 23, 2021 at 14:38 history edited YCor CC BY-SA 4.0
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Sep 23, 2021 at 14:21 history edited Jeremy Brazas CC BY-SA 4.0
Although I didn't forget about this question, I did neglect to make my question more detailed and explicit after the discussion in the comments. This has finally been done.
Sep 23, 2021 at 5:31 answer added Ethan Dlugie timeline score: 9
Mar 9, 2013 at 2:30 answer added Sergey Melikhov timeline score: 8
Jan 15, 2013 at 14:30 comment added Jeremy Brazas I did not mean to stress the "non-explicit homotopy" as much as "preferred CW-structure" but I will see if I can make the construction work for me. Regardless, I still hope someone might know the answer to my question. Thanks again!
Jan 15, 2013 at 0:09 comment added Misha Jeremy: The explicit construction Igor refers to is on the last page of math.cornell.edu/~hatcher/AT/AT-exercises.pdf
Jan 14, 2013 at 21:48 comment added Igor Belegradek Jeremy, actually the homotopy equivalence can be described explicitly (increasing dimension by one), i.e. the locally finite complex can be obtained as a mapping telescope of an exhausion of your given countable complex by finite subcomplexes (as explained somewhere in Hatcher's "Algebraic topology" text). Maybe this is be enough for your purposes.
Jan 14, 2013 at 15:21 comment added Jeremy Brazas Thank you for these comments @Igor and @Misha. I am aware of Whitehead's result, however, I don't want to lose my preferred CW-structure with a non-explicit homotopy equivalence. What I am asking seems plausible when you consider the 1-dimensional case. For instance, a countably infinite wedge of circles is not first countable but you can weaken the topology at the basepoint so that it embeds in $\mathbb{R}^2$. The homotopy inverse of the continuous (but non-open) identity map comes from collapsing a small closed ball about the basepoint.
Jan 14, 2013 at 4:53 comment added Misha Jeremy: See discussion and references at mathoverflow.net/questions/90570/…
Jan 13, 2013 at 19:49 comment added Igor Belegradek A classical result of Whitehead says: every countable finite dimensional CW complex is homotopy equivalent to a locally finite CW complex of the same dimension, which is of course metrizable.
Jan 13, 2013 at 17:24 history asked Jeremy Brazas CC BY-SA 3.0