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Jan 12, 2013 at 15:30 vote accept Ohad Asor
Jan 12, 2013 at 15:30 comment added Ohad Asor I got $-min(x,t)$
Jan 12, 2013 at 15:24 comment added Carlo Beenakker $g(x,t)={\rm max}(x-t,0)$
Jan 12, 2013 at 15:06 comment added Ohad Asor can you express it in terms of max/min?
Jan 12, 2013 at 14:32 comment added Carlo Beenakker @Ohad: the product of $x-t$ and $\theta(x-t)$ is a continuous function with a discontinuous first derivative, $dg/dt=-\theta(x-t)$.
Jan 12, 2013 at 13:11 comment added Ohad Asor so maybe I didn't get it.. doesn't Dirac and Heavyside discontinuous?
Jan 12, 2013 at 12:47 comment added Gerald Edgar This $g$ is continuous.
Jan 12, 2013 at 11:31 comment added Ohad Asor Hint: $g$ is continuous.
Jan 12, 2013 at 10:24 history answered Carlo Beenakker CC BY-SA 3.0