Skip to main content

Timeline for Primitive Cohomology Useful?

Current License: CC BY-SA 3.0

8 events
when toggle format what by license comment
Jan 11, 2022 at 19:55 comment added Z. M A technical question about Thm 1.5 in Deligne's paper: does a choice of $u\colon X\to X[2]$ correspond naturally to a splitting $X\simeq\bigoplus_i\pi_i(X)[i]$? It might be possible to prove this without reference to spectral sequences, I guess.
Jan 12, 2013 at 18:34 comment added ACL @LMN: Right, there is a hard Lefschetz theorem in étale cohomology, proved by Deligne in La conjecture de Weil, II (Section 4.1).
Jan 12, 2013 at 7:27 comment added LMN I guess here $\omega$ is $c_1()$ of very ample line bundle defining a $K$-rational map to projective space.
Jan 12, 2013 at 7:23 comment added LMN Aakumadula, are you saying that if we pick a Kahler form, and our variety is defined over a number field $K$, then the representation of the galois group $Gal(\bar{K}/K)$ on etale, and hence singular cohom, has each of the primitive cohomology groups as invariant subspaces? This is interesting.
Jan 12, 2013 at 7:21 comment added Dan Petersen What I was referring to is the very first proposition in Deligne's paper. The Leray SS comes from the equality $\mathrm R(g\circ f)_\ast = \mathrm R g_\ast \circ \mathrm R f_\ast$ in the derived category, where $g \colon S \to \mathrm{pt}$ is the projection to a point. The decomposition of $\mathrm Rf $ in the derived category implies the degeneration not only of this particular spectral sequence, but also of the ones obtained by replacing $g_\ast$ by any left exact functor, or more generally replacing $Rg_\ast$ by any cohomological functor.
Jan 12, 2013 at 7:19 comment added Venkataramana the point is that all the cohomology (of a smooth projective variety) is obtained from the primitive one by wedging with a Lefschetz class. Thus primitive cohomology is to be viewed as the subspace of highest weight vectors for the (Lefschetz) $SL_24 action. So, if you know for example, the Galois representations in the primitive cohomology, then you know the reps for all of the variety
Jan 12, 2013 at 7:08 comment added LMN Dan, this is very nice, Thanks! Could you say a few words about why we should think of the derived category result as better?
Jan 12, 2013 at 6:45 history answered Dan Petersen CC BY-SA 3.0