Timeline for The number of elements of order k in PGL(2, q)
Current License: CC BY-SA 3.0
3 events
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Jan 12, 2013 at 7:35 | comment | added | Mart | @Wei Zhou: By the sizes of conjugacy classes of PGL the size of the conjugacy class of an order-k cyclic subgroup $C$ must be $q(q-1)$ or $q(q+1)$. | |
Jan 12, 2013 at 5:43 | comment | added | Wei Zhou | @Mart: Sorry I have no reference on PGL at hand. But I think $1/2$ come from $|G:N_G(C)|$. | |
Jan 12, 2013 at 3:27 | history | answered | Wei Zhou | CC BY-SA 3.0 |