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Jan 10, 2013 at 15:53 comment added Michael Hardy I had concluded that, like the special case $1+\tan^2\theta=\sec^2\theta$ and unlike the formula for the tangent of a sum, this identity should not depend on the fact that the circle is parametrized by arc length. But then I proved it by relying on the identity $\sec(\alpha+\beta)=\sec\alpha\sec\beta/(1-\tan\alpha\tan\beta)$. So this posting confirms that I didn't need to do it that way.
Jan 10, 2013 at 15:43 vote accept Michael Hardy
Jan 8, 2013 at 9:49 history edited Hunter Spink CC BY-SA 3.0
Changed indices to j's
Jan 7, 2013 at 16:50 comment added Michael Hardy You seem to be using "$i$" both as the imaginary unit and as the index in $\theta_i$ and $\lambda_i$.
Jan 7, 2013 at 11:09 history answered Hunter Spink CC BY-SA 3.0