Timeline for $SU(2)$ and the three sphere [closed]
Current License: CC BY-SA 2.5
18 events
| when toggle format | what | by | license | comment | |
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Nov 26, 2014 at 7:27 | history | closed |
Ricardo Andrade Jeremy Rouse Felipe Voloch Chris Godsil Stefan Waldmann |
Not suitable for this site | |
| Nov 25, 2014 at 20:34 | review | Close votes | |||
| Nov 26, 2014 at 7:27 | |||||
| Feb 1, 2010 at 10:45 | answer | added | Misha Verbitsky | timeline score: 6 | |
| Jan 16, 2010 at 0:27 | comment | added | Kevin H. Lin | Not only is this easily found on google, it is also in any book on Lie groups. Yes, it is possible to learn things without using the internet. ;-) | |
| Jan 15, 2010 at 18:39 | comment | added | Ryan Budney | Mariano, certainly. But it seemed like Aston was wondering more what the map was, not so much the reasoning behind why the map is an isomorphism. MTS's reply below gives the technical issues of checking this map is the isomorphism. That said, I'm starting to agree with Benjamin. | |
| Jan 15, 2010 at 17:42 | history | edited | Aston Smythe | CC BY-SA 2.5 |
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| Jan 15, 2010 at 17:41 | comment | added | Aston Smythe | Yes, of course, I just mean homeomorphisn (or diffeomorphism if you want to get differential). | |
| Jan 15, 2010 at 16:43 | answer | added | Deane Yang | timeline score: 5 | |
| Jan 15, 2010 at 16:06 | comment | added | Mariano Suárez-Álvarez | @Ryan: You need to know that that action of $SU(2)$ on $S^3$ is transitive: $SU(2)$ also acts faithfully and unitarily on $\mathbb C^{23}$, yet it is not homeomorphic to $S^{22}$ :) | |
| Jan 15, 2010 at 15:42 | history | edited | Aston Smythe | CC BY-SA 2.5 |
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| Jan 15, 2010 at 15:12 | vote | accept | Aston Smythe | ||
| Jan 15, 2010 at 14:39 | history | edited | Steve Huntsman |
edited tags
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| Jan 15, 2010 at 9:51 | comment | added | Spinorbundle | I'm sorry, but I don't think that this is appropriate for MO, since the first 100 google results will give you the isomorphism. so -1 | |
| Jan 15, 2010 at 7:03 | comment | added | Ryan Budney | A simple answer -- $U(2)$ acts on $S^3$ since it acts on $\mathbb C^2$ by linear isometries. So $SU(2)$ also acts on $S^3$. That is the isomorphism, as it's a faithful representation. | |
| Jan 15, 2010 at 5:10 | answer | added | Anirbit | timeline score: 0 | |
| Jan 15, 2010 at 5:08 | answer | added | MTS | timeline score: 8 | |
| Jan 15, 2010 at 4:52 | history | asked | Aston Smythe | CC BY-SA 2.5 |