Skip to main content
9 events
when toggle format what by license comment
Jan 5, 2013 at 21:14 vote accept Michael Zieve
Jan 5, 2013 at 20:08 answer added Jason Starr timeline score: 24
Jan 5, 2013 at 15:54 answer added Alexandre Eremenko timeline score: 4
Jan 5, 2013 at 14:35 comment added Lubin Welcome, Mike!!
Jan 5, 2013 at 14:32 comment added Michael Zieve Yes, my question is for curves over the complex numbers.
Jan 5, 2013 at 14:30 comment added user30180 Is $C$ meant to be geometrically irreducible? Is the ground field algebraically closed? Of characteristic 0?
Jan 5, 2013 at 14:00 comment added Michael Zieve I mean a smooth projective curve. When I refer to "$f(x)=g(y)$", I mean the normalization of its projective closure.
Jan 5, 2013 at 12:52 comment added Dima Sustretov what do you mean by "curve"? since you mention a cover $C \to \mathbb{P}^1$, then it is probably a projective curve, but the nature of equation als suggests that you are talking about a plane affine curve.
Jan 5, 2013 at 12:33 history asked Michael Zieve CC BY-SA 3.0