Timeline for Solution to differential equation
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Jan 6, 2013 at 7:10 | comment | added | Robert Israel | Presumably. E.g. for $n=3$, numerical methods indicate the solution blows up before $t=-1$ for $y(-2) \ge .902$ approximately. | |
| Jan 4, 2013 at 21:16 | comment | added | djoke | Thanks! One more question. If the initial speed $y'(-2)=0$, can you have a similar conclusion? | |
| Jan 4, 2013 at 21:03 | vote | accept | djoke | ||
| Jan 4, 2013 at 21:03 | vote | accept | djoke | ||
| Jan 4, 2013 at 21:03 | |||||
| Jan 4, 2013 at 19:17 | comment | added | Robert Israel | You start with $f > 0$ at $t=-2$. $f$ is continuous. In order for $f$ to get to $0$, it would have to pass through the interval $(0, f(-2))$, which it can't because $df/dt > 0$ whenever $0 \le f \le 1$. | |
| Jan 4, 2013 at 16:38 | comment | added | djoke | Why you can assume that $f\in[0,1]$. You should prove that $f>0$? | |
| Jan 4, 2013 at 0:11 | history | edited | Robert Israel | CC BY-SA 3.0 |
added 230 characters in body
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| Jan 3, 2013 at 18:56 | history | edited | Robert Israel | CC BY-SA 3.0 |
added 511 characters in body
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| Jan 3, 2013 at 18:17 | comment | added | djoke | I updated the formulation. The question is can we find a global solution for example in (-2,-1). | |
| Jan 3, 2013 at 17:49 | history | answered | Robert Israel | CC BY-SA 3.0 |