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Jan 12, 2013 at 14:36 history edited Robert Bryant CC BY-SA 3.0
cleaned up the argument, corrected typos
Jan 4, 2013 at 17:37 history edited Robert Bryant CC BY-SA 3.0
fixed a formula
Jan 2, 2013 at 21:09 vote accept alvarezpaiva
Jan 2, 2013 at 21:09 comment added alvarezpaiva That's great. I had once used the trick of passing to the hemisphere transform to look at the cosine transform and it's nice to see that it can be used in this case as well. If we write the integral $Af$ as an integral over the whole sphere of the function $f$ multiplied by a Heaviside function, then we can differentiate again and reduce the problem to knowing the kernel of the spherical Radon transform, which I was planning to explain the students anyway.
Jan 2, 2013 at 20:26 history answered Robert Bryant CC BY-SA 3.0