Timeline for Generalization of the isoperimetric inequality
Current License: CC BY-SA 3.0
16 events
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Jan 4, 2013 at 19:41 | comment | added | Kevin R. Vixie | Hi Hans -- why did you delete your question about the distance between two curves? I had written up a somewhat detailed answer, but couldn't submit because the questions was deleted. (Your question was good by the way). If you are still interested you can email me at [email protected] and I will send you what I wrote, or undelete the question and I will post the answer. (I know this is an unusual use of the comments, but since you have no contact info on your user page this was the only option ;~) | |
| Jan 1, 2013 at 15:30 | comment | added | Hans-Peter Stricker | @Sergei: When you ask me: in both cases. | |
| Jan 1, 2013 at 15:27 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
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| Jan 1, 2013 at 14:51 | comment | added | Sergei Ivanov | This is certainly false for arbitrary pairs $\Gamma,\Gamma'$, just by counting the degrees of freedom. Concerning the ellipses, are you interested in the case when both curves are ellipses, or one of them? | |
| Dec 31, 2012 at 17:27 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
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| Dec 31, 2012 at 17:26 | comment | added | Hans-Peter Stricker | @Sergei: You are right, I corrected it again. | |
| Dec 31, 2012 at 17:06 | comment | added | Sergei Ivanov | Your formula for $\Omega$ is still not good. You are integrating a full derivative (and singularities are only at points where the curvature is zero), so the result is always 0. | |
| Dec 31, 2012 at 16:32 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
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| Dec 31, 2012 at 10:48 | comment | added | Hans-Peter Stricker | @Alexandre: Absolutely, thanks for the improvement! | |
| Dec 30, 2012 at 21:09 | comment | added | Alexandre Eremenko | Did I understand your question correctly (I edited it according to my understanding:-) ? | |
| Dec 30, 2012 at 21:08 | history | edited | Alexandre Eremenko | CC BY-SA 3.0 |
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| Dec 30, 2012 at 20:58 | comment | added | Hans-Peter Stricker | $\Omega = 0$ is supposed to mean "constant curvature". | |
| Dec 30, 2012 at 19:57 | comment | added | Pietro Majer | Is the formula for Ω what you really mean? Here Ω=0 implies γ′′′=0 , that is $\gamma(s)=as^2+bs+c$, right? | |
| Dec 30, 2012 at 18:00 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
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| Dec 30, 2012 at 17:48 | history | asked | Hans-Peter Stricker | CC BY-SA 3.0 |