Timeline for A question on almost simple groups
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
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Dec 31, 2012 at 16:34 | comment | added | majid arezoomand | A very nice proof! | |
Dec 31, 2012 at 10:35 | history | edited | Geoff Robinson | CC BY-SA 3.0 |
added 1083 characters in body
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Dec 31, 2012 at 7:39 | history | edited | Geoff Robinson | CC BY-SA 3.0 |
typos
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Dec 31, 2012 at 3:34 | comment | added | Mart | @Geoff Robinson: Thank you very much, it was most helpful! | |
Dec 30, 2012 at 20:01 | history | edited | Geoff Robinson | CC BY-SA 3.0 |
Show $p$ does divide $|S|$ in response to Mart's question.
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Dec 30, 2012 at 18:09 | comment | added | Derek Holt | Yes that is indeed a more direct argument! | |
Dec 30, 2012 at 17:38 | comment | added | Mart | @Geoff Robinson: Thanks. By Derek's answer if $S\unlhd G$ with $S$ simple and $G\leq Aut(S)$, then $p$ is prime divisor of $S$. Whether by your answer it implies that $p$ is prime divisor of $S$? | |
Dec 30, 2012 at 16:27 | history | answered | Geoff Robinson | CC BY-SA 3.0 |