Timeline for Isometry of K3 surface.
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Dec 30, 2012 at 23:36 | comment | added | Johannes Nordström | Sure, that tells you that for any automorphism of $S$ (of finite order at least) there exists some invariant Kähler class, and hence an invariant Ricci-flat Kähler metric. But it does not mean that a given Ricci-flat Kähler metric is invariant, which is what your question seems to ask. | |
| Dec 30, 2012 at 23:04 | comment | added | Zheng | One can average the Kahler form and get invariant Kahler class. For such a Kahler metric, $g$ is invariant and thus $\iota$ is an isometry. This works for any holomorphic $G$-action. | |
| Dec 30, 2012 at 16:03 | history | answered | Johannes Nordström | CC BY-SA 3.0 |