Timeline for A Property of Finite Rings
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 23, 2013 at 11:32 | comment | added | Tom Goodwillie | Let $C$ be the set of all ordered pairs $(x,y)\in R\times R$ such that $xy=0$. Then $|C|$ is the sum, over all $x\in R$, of $|A(x)|$. On the other hand $C$ is also the sum, over all $y\in R$, of $|B(y)|$. | |
| Apr 23, 2013 at 0:00 | comment | added | Tom Goodwillie | I gave the reason. | |
| Apr 22, 2013 at 18:36 | vote | accept | CommunityBot | ||
| Apr 22, 2013 at 18:36 | comment | added | user30230 | @Tom: I am afraid the argument is not right. How do you conclude that the sum of all $a(x)$'s and the sum of all $b(x)$'s are equal ?! | |
| Dec 30, 2012 at 7:21 | vote | accept | CommunityBot | ||
| Apr 22, 2013 at 18:36 | |||||
| Dec 30, 2012 at 7:21 | vote | accept | CommunityBot | ||
| Dec 30, 2012 at 7:21 | |||||
| Dec 30, 2012 at 0:56 | history | answered | Tom Goodwillie | CC BY-SA 3.0 |