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Dec 25, 2012 at 23:55 comment added Andrew McHugh @Dmitri, Yes, this answers my question. Thank you!
Dec 25, 2012 at 11:19 vote accept Andrew McHugh
Dec 25, 2012 at 2:33 comment added Dmitri Panov Yes. provided I am answering indeed the question Andrew had in mind.
Dec 25, 2012 at 2:32 history edited Dmitri Panov CC BY-SA 3.0
added 4 characters in body
Dec 25, 2012 at 1:39 comment added Noam D. Elkies Right $-$ it's enough for the odd dimensions to be distinct (and neither equal $1$).
Dec 25, 2012 at 1:15 comment added YangMills oops, I guess I read the OP's condition as $b_1=b_2=b_3=...=b_n=0$, which is apparently not what was asked!
Dec 25, 2012 at 1:14 comment added YangMills yes, but it won't satisfy the OP's condition on the Betti numbers!
Dec 25, 2012 at 1:09 history answered Dmitri Panov CC BY-SA 3.0