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Dec 28, 2012 at 8:35 vote accept Christian Rinderknecht
Dec 25, 2012 at 14:05 answer added Christian Rinderknecht timeline score: 1
Dec 25, 2012 at 14:03 history edited Christian Rinderknecht CC BY-SA 3.0
Acknoledged the solution of Terry Tao.
Dec 25, 2012 at 13:10 history edited Christian Rinderknecht CC BY-SA 3.0
Fixed a sign
Dec 25, 2012 at 12:55 history edited Christian Rinderknecht CC BY-SA 3.0
In response to comment, I fixed the equivalent condition.
Dec 24, 2012 at 8:07 comment added Terry Tao I think all that the authors are doing here is expanding $d(k) = \sum_{k = k' h} 1$, then interchanging summations, then relabeling $k'$ as $k$ (and also shifting $h$ by $1$).
Dec 24, 2012 at 7:42 answer added Brendan McKay timeline score: 3
Dec 24, 2012 at 5:47 comment added Zev Chonoles Crossposted to math.SE: math.stackexchange.com/q/264137/264 In the future, please wait some time before posting your question in multiple fora, and when you do, provide links to the other posts - as you can imagine, it would be frustrating for someone to put time into answering your question here, only to see hear from you that you'd already gotten the solution elsewhere.
Dec 24, 2012 at 5:35 history asked Christian Rinderknecht CC BY-SA 3.0