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Dec 24, 2012 at 0:22 history edited Deane Yang CC BY-SA 3.0
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Dec 22, 2012 at 19:47 history edited Deane Yang CC BY-SA 3.0
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Dec 22, 2012 at 19:43 comment added Deane Yang It's worth noting that a valuation is not the same as a measure. For example, on $R^n$, you could let $m(A)$ be the surface area of the boundary of $A$ and restrict to sets with finite surface area. This is a valuation that can be used to define center of mass. But I believe you just get the same one you get with volume.
Dec 22, 2012 at 19:37 history edited Deane Yang CC BY-SA 3.0
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Dec 22, 2012 at 2:33 history answered Deane Yang CC BY-SA 3.0