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Dec 20, 2012 at 16:51 comment added LMN @Johannes, in regards to your answer to #1, you get that the map $f$ induces an isomorphism on the first $n-1$ homotopy groups. I don't see how this allows you to deduce that the cohomology groups of $M$ are the same as those of $K$. Hurewicz's theorem doesn't seem to help.
Dec 19, 2012 at 23:26 comment added Johannes Ebert Odd-dimensional manifolds have two middle dimensions to control, so in that case, the situation is more complicated.
Dec 19, 2012 at 21:35 comment added LMN Daniel, right - "odd" should be "even".
Dec 19, 2012 at 21:31 comment added Daniel Litt @LMN: Even-dimensional manifolds are the ones with "middle cohomology groups."
Dec 19, 2012 at 21:19 comment added LMN Johannes, I'm having a little trouble translating the language into things I am familiar with. Are you saying that the answer to my question #1 is yes (but if the dimension is odd we might not be able to control the middle cohomology group).
Dec 19, 2012 at 21:07 history edited Dmitri Pavlov CC BY-SA 3.0
fixed a markup problem
Dec 19, 2012 at 21:01 history answered Johannes Ebert CC BY-SA 3.0