Timeline for Why is there a unique increasing maximal path in any Bruhat interval under any reflection order?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Jan 2, 2013 at 21:24 | answer | added | Hugh Thomas | timeline score: 1 | |
| Dec 23, 2012 at 3:33 | history | edited | Michael Zhong | CC BY-SA 3.0 |
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| Dec 22, 2012 at 5:36 | comment | added | Harry Huang | Seriously, those armed with the root version of reflection order are not ready to deal with the reflections... I suggest you provide the theorem on the order-preserving bijection between positive roots and reflections. | |
| Dec 22, 2012 at 3:16 | history | undeleted | Michael Zhong | ||
| Dec 22, 2012 at 3:15 | history | edited | Michael Zhong | CC BY-SA 3.0 |
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| Dec 22, 2012 at 2:59 | history | deleted | Michael Zhong | ||
| Dec 22, 2012 at 2:43 | history | edited | Michael Zhong | CC BY-SA 3.0 |
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| Dec 19, 2012 at 0:48 | comment | added | Alexander Woo | Michael: Many people who might have an answer to your question (myself included) don't remember the details of the increasing-Bruhat-path interpretation of $R$-polynomials and are too lazy to reach for their copy of Bjorner--Brenti to find it. (In my case, it's not just laziness; I'm about 1000 miles away from my office at the moment.) Providing some partial explanation might help you get an answer. | |
| Dec 18, 2012 at 15:35 | history | asked | Michael Zhong | CC BY-SA 3.0 |