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Dec 21, 2012 at 17:05 answer added John Cremona timeline score: 10
Dec 18, 2012 at 7:51 comment added François Brunault @Chandan : Thanks for this reference. I should have said "separable base change" in the above comment. As far as the Fermat curve of degree $n$ is concerned, everything is fine as long as the characteristic of $K$ doesn't divide $n$ : the curve is absolutely irreducible, smooth, and the $K$-vector space of regular differentials on it has dimension $(n-1)(n-2)/2$.
Dec 17, 2012 at 12:23 comment added Chandan Singh Dalawat @François : Voir Genus change in inseparable extensions of function fields par John Tate (ams.org/journals/proc/1952-003-03/S0002-9939-1952-0047631-9/…).
Dec 17, 2012 at 12:08 answer added user9072 timeline score: 7
Dec 17, 2012 at 12:07 vote accept joro
Dec 17, 2012 at 12:01 comment added François Brunault The genus of a curve is invariant under base change.
Dec 17, 2012 at 11:19 answer added Qiaochu Yuan timeline score: 8
Dec 17, 2012 at 11:14 history edited joro CC BY-SA 3.0
Added coprimality to avoid scaling a single solution
Dec 17, 2012 at 11:03 comment added Chandan Singh Dalawat Isn't there a formula for the genus of a plane curve in terms of its degree ?
Dec 17, 2012 at 10:32 history asked joro CC BY-SA 3.0