Timeline for Can FLT fail with a parametrization over some extension of Z?
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
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Dec 21, 2012 at 17:05 | answer | added | John Cremona | timeline score: 10 | |
Dec 18, 2012 at 7:51 | comment | added | François Brunault | @Chandan : Thanks for this reference. I should have said "separable base change" in the above comment. As far as the Fermat curve of degree $n$ is concerned, everything is fine as long as the characteristic of $K$ doesn't divide $n$ : the curve is absolutely irreducible, smooth, and the $K$-vector space of regular differentials on it has dimension $(n-1)(n-2)/2$. | |
Dec 17, 2012 at 12:23 | comment | added | Chandan Singh Dalawat | @François : Voir Genus change in inseparable extensions of function fields par John Tate (ams.org/journals/proc/1952-003-03/S0002-9939-1952-0047631-9/…). | |
Dec 17, 2012 at 12:08 | answer | added | user9072 | timeline score: 7 | |
Dec 17, 2012 at 12:07 | vote | accept | joro | ||
Dec 17, 2012 at 12:01 | comment | added | François Brunault | The genus of a curve is invariant under base change. | |
Dec 17, 2012 at 11:19 | answer | added | Qiaochu Yuan | timeline score: 8 | |
Dec 17, 2012 at 11:14 | history | edited | joro | CC BY-SA 3.0 |
Added coprimality to avoid scaling a single solution
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Dec 17, 2012 at 11:03 | comment | added | Chandan Singh Dalawat | Isn't there a formula for the genus of a plane curve in terms of its degree ? | |
Dec 17, 2012 at 10:32 | history | asked | joro | CC BY-SA 3.0 |