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Jun 23 at 23:36 history edited David Roberts CC BY-SA 4.0
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Mar 26, 2013 at 18:26 comment added Tobias Diez Another enquiry regarding the dependence on the exhaustion and the metric in the non-compact case, as I do not see it. I suspect you are referring to the seminorms $p_{K, k}(f) = sup_{x \in K}(|\nabla^i f (m) |)$. Let $(K_n)$ and $(L_i)$ be two different exhaustions by compact sets. By a standard argument each $L_i$ can be absorbed by one $K_n$, $\L_i \subseteq K_n$. Than trivially $p_{L_i} \leq p_{K_n}$ and the topology is independent on the choice of exhaustion. Furthermore, the metric always gets evaluated over compact sets and so each choice of metric should give equivalent topologies.
Jan 2, 2013 at 13:15 history edited Peter Michor CC BY-SA 3.0
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Jan 2, 2013 at 13:06 history edited Peter Michor CC BY-SA 3.0
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Jan 2, 2013 at 11:01 vote accept Tobias Diez
Jan 2, 2013 at 10:52 comment added Tobias Diez Thank you for pointing out the dependence on the construction. Do you know any independence-results if I fix a (pseudo-)Riemannian metric (even Lorentzian manifold if necessary) on the base space and restrict to affine or vector bundles (to include the additive structure Andrew Stacey pointed out)?
Jan 2, 2013 at 10:13 vote accept Tobias Diez
Jan 2, 2013 at 11:01
Dec 17, 2012 at 8:03 history answered Peter Michor CC BY-SA 3.0