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Dec 15, 2012 at 20:41 comment added Mike Shulman @Ronnie: It's true that every fibration admits a canonical "ana-cleavage". Is that what you were asking?
Dec 12, 2012 at 23:39 comment added David Roberts @Ronnie - there is definitely a relation to fibrations, but Jean Benabou would be furious if I didn't say that one can use what he calls distributors (but almost everyone else calls profunctors) to deal with this issue (and these have a longer history). There is a property of an anafunctor called saturation, and saturated anafunctors between categories are equivalent to representable distributors/profunctors, so you can approach it from either side. However, you don't need the relation between the two to recover the sort of thing you are thinking of using anafunctors.
Dec 12, 2012 at 17:58 comment added Almeo Maus Thank you very much for your answer! I will take time to understand the notion, that seems to help define those functors "defined up to (canonical) isomorphisms". – Almeo Maus 0 secs ago
Dec 12, 2012 at 11:32 comment added Ronnie Brown @david: Has this idea been ap[plied to fibrations of categories replacing the notion of cleavage? I recall Benabou was not keen on assuming that fibrations had a cleavage.
Dec 11, 2012 at 23:44 history answered David Roberts CC BY-SA 3.0