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Dec 11, 2012 at 5:56 comment added Sasha Of course it is not an isomorphism of groups, but still it gives an isomorphism of algebras.
Dec 11, 2012 at 5:47 comment added Catherine @darij grinberg : Yes, I figured that out an instant ago, so I switched the answer to yours.
Dec 11, 2012 at 5:46 comment added darij grinberg It's not a map of groups, though, unless you assume $G$ to be abelian.
Dec 11, 2012 at 5:45 vote accept Catherine
Dec 11, 2012 at 5:46
Dec 11, 2012 at 5:43 history answered Sasha CC BY-SA 3.0