Timeline for On a inequality [closed]
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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Dec 12, 2012 at 19:23 | vote | accept | ljjpfx | ||
Dec 12, 2012 at 19:23 | |||||
Dec 11, 2012 at 17:07 | history | closed |
Yemon Choi Andrés E. Caicedo Pietro Majer Michael Renardy user9072 |
not a real question | |
Dec 11, 2012 at 14:14 | answer | added | Selim | timeline score: 1 | |
Dec 11, 2012 at 11:04 | history | edited | ljjpfx | CC BY-SA 3.0 |
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Dec 10, 2012 at 12:18 | history | edited | Charles Matthews | CC BY-SA 3.0 |
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Dec 10, 2012 at 12:17 | answer | added | Charles Matthews | timeline score: 0 | |
Dec 10, 2012 at 11:53 | comment | added | user16517 | My guess is that a more meaningful inequality would have $C$ depend only on the $t_i$, but that's for you to decide. | |
Dec 10, 2012 at 11:52 | comment | added | user16517 | Suppose Delio's comments were imposed, i.e. you look only at $a_i \geq 0$ (I see you have $C>0$ now.). As it is now you've "given too much" to be a meaningful inequality, because you've given the $a_i , b_i,$ and $t_i$. This means that the right hand side is fully determined, as is everything on the left hand side except for C. Also both sides are nonnegative. Thus, the question reduces to asking if the left hand side is nonzero, whether there is a positive number $C \leq $ to the quotient of two positive numbers, which is always a positive number so yes. | |
Dec 10, 2012 at 11:11 | comment | added | Delio Mugnolo | ...or $a_i\ge 0$, of course. | |
Dec 10, 2012 at 11:09 | comment | added | Delio Mugnolo | Your statement cannot be true. You need at very least to ask whether there is $C>0$ such that [...] and to impose that also $a_i>0$ (otherwise you could simply obtain the reverse inequality simply by flipping the sign of $a_i$). | |
Dec 10, 2012 at 10:49 | history | edited | ljjpfx | CC BY-SA 3.0 |
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Dec 10, 2012 at 10:37 | history | asked | ljjpfx | CC BY-SA 3.0 |