Timeline for Does a weaker condition than vanishing derivative imply a function being constant?
Current License: CC BY-SA 3.0
2 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Dec 9, 2012 at 19:24 | comment | added | qianzhang | Bazin, thank you for your answer. I think the dominated convergence assumption is too strong for me, and I am only interested in pointwise convergence without further condition. I am sorry for not excluding this situation in my question. | |
Dec 9, 2012 at 19:16 | history | answered | Bazin | CC BY-SA 3.0 |