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Timeline for Is this bounded?

Current License: CC BY-SA 3.0

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Dec 6, 2012 at 14:39 comment added Ben Barber Palt, I was considering the complete graph on $v_1, \ldots, v_{m+1}$, which should cover all possible interpretations of the question as by adding more edges the smallest angle cannot get larger. The angle you specify at the end of your comment is the one I'm claiming is $\pi/2m$; do you get a different value?
Dec 6, 2012 at 14:35 comment added Palt Ben, all the edges are included to form the angles, sorry for unclearness. The smallest angle obtained using the centre would be an interior angle of the triangle that contains the centre, a vertex on the boundary and its farthest vertex on the boundary, so it can be much less than $\pi/2m$.
Dec 6, 2012 at 14:20 history answered Ben Barber CC BY-SA 3.0