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Jun 25, 2013 at 3:02 review Late answers
Jun 25, 2013 at 13:49
Dec 7, 2012 at 13:26 comment added Stephan E. Aha - thanks! So you mean that if $f=\sum_{n=1}^\infty c(n)q^n$, I don't take the form [ g = \sum_{n=1}^\infty \chi(n)c(n)q^n ] but I write $g$ as $g=f_\chi + g'$, where $f_\chi$ is a newform? This would make perfect sense, of course. (But it is a bit confusing that people write in several places things like $f$ has CM if and only if it is equal to a twist of itself.)
Dec 7, 2012 at 3:41 comment added Rob Harron So, you start with a normalized newform f and then you twist by some $\chi$ and let $f_\chi$ be the associated newform. Then, $f=f_\chi$ for some $\chi$ if $f$ is CM.
Dec 6, 2012 at 9:36 history answered Stephan E. CC BY-SA 3.0