Timeline for ODE's without a Lipschitz condition
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
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Dec 5, 2012 at 19:54 | comment | added | Will Jagy | @Pietro, yes. There is a similar example as an answer. | |
Dec 5, 2012 at 19:39 | answer | added | Dirk | timeline score: 7 | |
Dec 5, 2012 at 19:05 | comment | added | Pietro Majer | Will, I think you mean $y=x^2/4$. Note that there is a continuum of solutions: $(x-a) _ + ^2/4$ . | |
Dec 5, 2012 at 19:03 | comment | added | Daniel Spector | Ha. I was teeing the answer while my son watches Dumbo, and almost simultaneously was the comment from Will, as well as the answers from Michael, Vaughn and Pietro. The former gave my reply - Lipschitz is about uniqueness, the latter three contributed on your question, existence. | |
Dec 5, 2012 at 19:01 | comment | added | Vaughn Climenhaga | As the 3 simultaneous answers below point out, existence follows from continuity. I've deleted my answer as Pietro gives a better explanation. | |
Dec 5, 2012 at 18:59 | vote | accept | Arthur | ||
Dec 5, 2012 at 18:57 | answer | added | Daniel Spector | timeline score: 6 | |
Dec 5, 2012 at 18:55 | answer | added | Pietro Majer | timeline score: 17 | |
Dec 5, 2012 at 18:54 | answer | added | Michael Renardy | timeline score: 2 | |
Dec 5, 2012 at 18:36 | history | asked | Arthur | CC BY-SA 3.0 |